If we start with Townsend’s reported numbers….
The basin is 24 inches deep and uses 260,000 gallons when full. The college estimates .25 inch evaporation a day. That would mean, if left alone the pool would empty every 96 days. (.25*24)
A year is 365.2422 days long. So the pool would be filled 3.8046 times a year. (365.2422/96).
At 260000 gallons a fill up that would be 989197.625 gallons a year. (3.8046*260,000)
If a student uses 100 gallons a day she would use 36524.22 gallons a year. That means the water dome would use about as much as 27 such students a year. (989197.625 / 36524.22)
If a student uses 150 gallons a day he would use 54786.33 gallons a year. That means the water dome would use about as much as 18 such students a year. (989197.625 / 54786.33 )
I spoke to some folks at Lakeland’s Water Department. A key fact is there is a really cumbersome formula used to determine what is the per-capita* water usage in the city. However, 70% to 75% of Lakeland Water customers use less than 7000 gallons a month.
Using that number as our “mostly” worst case, our Lakeland customer would use 84,000 gallons of water a year. (12 * 7000) That means the water dome would use a little less than 12 of those customers would use. ( 989197.625 / 84,000 = 11.7762 )
Not quite a subdivision, but certainly my street.
The university is trying to control water use by limiting the time the fountain is open. State rules limit fountains to less than 8 hours a day. The college has published a schedule of a little over 3 hours a day. **
One point I haven’t seen mentioned is, that since the college didn’t get a permit for the fountain’s higher than before water usage, they have to cut back elsewhere.
The gist is: the college can’t use any more water than they were before the water dome.
* – “per capita” — per person
** – (Hat tip to Billy Townsend.)